如何测试ws-security？
我即将使用Web服务开发Web应用程序。我已经调整了jax-ws和ws-security。我使用soapUI并发送了下一个请求：
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:soap="..." >
<soapenv:Header>
<wsse:Security xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd" soapenv:mustUnderstand="1">
<wsu:Timestamp xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd" wsu:Id="Timestamp-2">
<wsu:Created>2011-11-11T00:05:05.044Z</wsu:Created>
<wsu:Expires>2012-11-11T00:10:05.044Z</wsu:Expires>
</wsu:Timestamp>
<wsse:UsernameToken xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd" wsu:Id="UsernameToken-1">
<wsse:Username>user</wsse:Username>
<wsse:Password>password</wsse:Password>
</wsse:UsernameToken>
</wsse:Security>
</soapenv:Header>
<soapenv:Body>
<soap:foo>
<arg0>1</arg0>
</soap:foo>
</soapenv:Body>
</soapenv:Envelope>
@Resource
WebServiceContext context;
...
private static final String PRINCIPAL_RESULT = "wss4j.principal.result";
...
WSUsernameTokenPrincipal wsutp = (WSUsernameTokenPrincipal) context.getMessageContext().get(PRINCIPAL_RESULT);
..
String user = wsutp.getName()
String password = wsutp.getPassword();
没有找到相关结果
已邀请:
2 个回复
蹄寄噬非芹
//You can mock concrete classes, not only interfaces LinkedList mockedList = mock(LinkedList.class); //stubbing when(mockedList.get(0)).thenReturn("first"); when(mockedList.get(1)).thenThrow(new RuntimeException());WSUsernameTokenPrincipal mockedWsutp = mock(WSUsernameTokenPrincipal.class); when(mockedWsutp.getName()).thenReturn("TheNameRequiredForYourTestCase"); ...糖固傻染