SQL查询中的复杂计算

我昨天用相同的代码发布了一个类似的问题,我已经重写了,它应该是一个新规范的完美,但由于某种原因它不起作用。 我正在使用Oracle 10g Express。 以下代码正在计算收入最高的10%的律师。
CREATE VIEW rich_solicitors AS
select notes.time_spent*rate.rate_amnt+coalesce(special_rate.s_rate_amnt,0)
AS solicitor_made, notes.solicitor_id
FROM notes, rate, solicitor_rate, solicitor, case, contract, special_rate
WHERE notes.solicitor_id = solicitor.solicitor_id
AND solicitor.solicitor_id = solicitor_rate.solicitor_id
AND solicitor_rate.rate_id = rate.rate_id
AND notes.case_id = case.case_id
AND case.contract_id = contract.contract_id
AND contract.contract_id = special_rate.contract_id (+)
ORDER BY -solicitor_made;


SELECT * FROM rich_solicitors
WHERE ROWNUM <= (SELECT COUNT(*)/10 FROM rich_solicitors);
我需要计算出去年的前10%,我认为这就像将start_date和expiry_date添加到SELECT并添加以下WHERE函数一样简单:
AND contract.start_date >= 01-01-10
AND contract.expiry_date <= 01-01-11
我使用TO_DATE核心插入日期。我的讲师花了一个小时与我一起研究为什么这不起作用但无济于事。 它一直在返回错误 - ORA-00932:不一致的数据类型:预期CHAR得到NUMBER 我也尝试定义日期格式,但仍然返回相同的错误
CREATE VIEW rich_solicitors1 AS
SELECT  notes.time_spent*rate.rate_amnt+coalesce(special_rate.s_rate_amnt,0) AS solicitor_made, notes.solicitor_id, TO_CHAR(contract.start_date, 'DD-MM-YY'), TO_CHAR(contract.expiry_date, 'DD-MM-YY')
FROM notes, rate, solicitor_rate, solicitor, case, contract, special_rate
WHERE notes.solicitor_id = solicitor.solicitor_id
AND solicitor.solicitor_id = solicitor_rate.solicitor_id
AND solicitor_rate.rate_id = rate.rate_id
AND notes.case_id = case.case_id
AND case.contract_id = contract.contract_id
AND contract.contract_id = special_rate.contract_id (+)
AND contract.start_date >= 01-01-10
AND contract.expiry_date <= 01-01-11
ORDER BY -solicitor_made;
有任何想法吗? 非常感谢,任何批评都非常感谢,我是一名学生,在我的第一步,大约9天前,我根本没有SQL知识。     
已邀请:
你能尝试用NVL功能代替你的合并吗?
SELECT  notes.time_spent*rate.rate_amnt+NVL(special_rate.s_rate_amnt,0) 
AS solicitor_made, notes.solicitor_id, TO_CHAR(contract.start_date, 'DD-MM-YY'), 
TO_CHAR(contract.expiry_date, 'DD-MM-YY') 
FROM notes, rate, solicitor_rate, solicitor, case, contract, special_rate 
WHERE notes.solicitor_id = solicitor.solicitor_id 
AND solicitor.solicitor_id = solicitor_rate.solicitor_id 
AND solicitor_rate.rate_id = rate.rate_id AND notes.case_id = case.case_id 
AND case.contract_id = contract.contract_id 
AND contract.contract_id = special_rate.contract_id (+) 
AND contract.start_date >= to_date('01-01-10','MM-DD-YY')
AND contract.expiry_date <= to_date('01-01-11' ,'MM-DD-YY')
ORDER BY solicitor_made
    
Phil,你使用ROWNUM的查询将无法通过我能想到的任何“top”定义获得前10%。 一个例子是:
SELECT * FROM (
  SELECT solicitor_made, solicitor_id
        ,NTILE(10) OVER (ORDER BY solicitor_made DESC) decile
  FROM rich_solicitors
) WHERE decile = 1;
编辑 刚刚注意到你的视图定义中有一个ORDER BY。在这种情况下,您的ROWNUM方法将起作用。通常我建议不要在视图定义中放置ORDER BY。     

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