Actionscript中的简单事件链接。如何强制显示刷新？
我正在尝试采用先前并行运行多个远程对象调用的进程，并使它们以串行方式运行。
我知道这是一种hackish方法（bandaid！），但到目前为止我的方法是采用这个for循环来启动每个并行请求：
（原始代码）
for (i = 0; i < _processQ.length; i++){
fObj = _processQ.getItemAt(i);
f = fObj.Name;
fObj.Progress = "Processing...";
ro.process(gameid,f);
}
for (i = 0; i < _processQ.length; i++){
fObj = _processQ.getItemAt(i);
f = fObj.Name;
fObj.Progress = "Processing...";
ro.process(gameid,f);
//pause this loop until a result is returned from the request that was just made.
_pause_queue = true;
while(_pause_queue){
//do nothing
}
}
_pause_queue
DoEvents
没有找到相关结果
已邀请:
3 个回复
淘圃跺枯替
// A process queue item method protected function processItemInQueue():Void{ if(_processQ.length > 0){ fObj = _processQ.pop(); f = fObj.Name; fObj.Progress = "Processing..."; ro.process(gameid,f); } }protected function roResultHandler(event:ResultEvent):void{ // process results // process next item in queue processItemInQueue(); }嘘伪
桔马牛
function outerFunction() { var queue = new SomeAsyncProcessor(); for (i = 0; i < _processQ.length; i++){ queue.addProcess(_processQ.getItemAt(i)); } queue.addEventListener('complete', handleProcess); queue.start(); game.pause(); } function handleProcess(event) { var processor = event.currentTarget as SomeAsyncProcessor(); process.removeEventListener('complete', unpause); game.unpause(); }