评论会员：游客 时间：2012/02/07
kumar_jadhav:试试吧..codeprelang="SQL"spanclass="code-keyword"SELECT/spanenames,COUNT(enames)spanclass="code-keyword"AS/span[CountOfEnames]spanclass="code-keyword"FROM/spanempspanclass="code-keyword"GROUP/spanspanclass="code-keyword"BY/spanenamesspanclass="code-keyword"HAVING/spanCOUNT(enames)>1/pre/code
losmac
评论会员：游客 时间：2012/02/07
。该库将满足您的所有需求，预定作业:imgsrc=的问候，曼弗雷德