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IM禁用pageLoad的按钮。和我的程序做的一切活动,并应使按钮。但按钮被禁用的页面重载。所以我想以计数的页面加载和计数(页面加载)一样,如果是多个,则不要禁用它把一个条件。我怎么做呢?我可以得到的代码请。我尝试它没有工作

回答

评论会员:游客 时间:2012/02/07
AnujBanka的:只要把你的代码如果不pageIsPostBack然后您的代码...ENDIF
alrosan
评论会员:游客 时间:2012/02/07
codeprelang="cs"spanclass="code-keyword"protected/spanspanclass="code-keyword"void/spanPage_Load(spanclass="code-keyword"object/spansender,EventArgse){spanclass="code-keyword"if/span(!IsPostBack){spanclass="code-keyword"if/span(Application[spanclass="code-string""/spanspanclass="code-string"visits"/span]==spanclass="code-keyword"null/span){Application[spanclass="code-string""/spanspanclass="code-string"visits"/span]=spanclass="code-digit"1/span;}spanclass="code-keyword"else/span{spanclass="code-keyword"int/spanvisits=(spanclass="code-keyword"int/span)Application[spanclass="code-string""/spanspanclass="code-string"visits"/span];visits++;Application[spanclass="code-string""/spanspanclass="code-string"visits"/span]=visits;spanclass="code-keyword"if/span(visits>spanclass="code-digit"1/span){myButton.Enabled=spanclass="code-keyword"true/span;}}} }/pre/code