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如何使用ListView的价值观:

<asp:ListView ID="ListView1" runat="server" DataKeyNames="Service_ID"

            DataSourceID="SqlDataSource3" InsertItemPosition="FirstItem"

            ItemPlaceholderID="Placeholder1" Visible="False">

            <LayoutTemplate>

                <table ID="table1" runat="server" border="1" width=100%>

                    <tr>

                        <th class="subheader" colspan="3">

                            Services</th>

                        <th>

                            <asp:LinkButton ID="lnkService" runat="server"></asp:LinkButton>

                        </th>

                    </tr>

                    <tr ID="Placeholder1" runat="server">

                    </tr>

                </table>

            </LayoutTemplate>

            <ItemTemplate>

                <tr>

                    <td>

                        <%#Eval("Service_Name")%>

                    </td>

                    <td>

                        <asp:CheckBox ID="chkService" runat="server" />

                    </td>

                    <td>

                        <asp:TextBox ID="txtServices" runat="server"></asp:TextBox>

                    </td>

                </tr>

            </ItemTemplate>

            <InsertItemTemplate>

                <asp:LinkButton ID="Link1" runat="server" Text="Edit"></asp:LinkButton>

            </InsertItemTemplate>

        </asp:ListView>
{C}
<asp:DropDownList ID="ddlServer" runat="server" CssClass="dropdownlistLarge" Font-Size="10"

            AutoPostBack="true" OnSelectedIndexChanged="ddlServer_SelectedIndexChanged" DataTextField="Server_Name"

             DataValueField="Server_ID" DataSourceID="SqlDataSource1">

                      </asp:DropDownList>
如何访问ListView项目下拉选择,在我可以插入复选框,并在ListView的文本框的值是相同的一个gridview绑定到特定的列

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