我怎么能设置的MenuItem IsEnable财产时opeing的ContextMenu。
代码如下:
m_ProjectMenu = new ContextMenu();
MenuItem MenuItem_Submit = new MenuItem();
MenuItem_Submit.Header = "Submit";
m_ProjectMenu.Items.Add(MenuItem_Submit);
MenuItem MenuItem_Delete = new MenuItem();
MenuItem_Delete.Header = "Delete";
m_ProjectMenu.Items.Add(MenuItem_Delete);
m_ProjectViewGrid.ContextMenu = m_ProjectMenu;
m_ProjectViewGrid.ContextMenuOpening += new ContextMenuEventHandler(m_ProjectViewGrid_ContextMenuOpening);
我怎样才能得到它的头或名称的MenuItem,我想它禁用根据一些condition.I试图FindName的ContextMenu方法,但我得到一个空。
有任何人,我该怎么做。
谢谢| Alimjan亚辛